(18a^-2b^10)/(-3a^-5b^-3)

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Solution for (18a^-2b^10)/(-3a^-5b^-3) equation: 


D( x )

-3*a^-5*b^-3 = 0

-3*a^-5*b^-3 = 0

-3*a^-5*b^-3 = 0

-3*a^-5*b^-3 = 0

x naleu017Cy do R

x belongs to the empty set

(18*a^-2*b^10)/(-3*a^-5*b^-3) = 0

x belongs to the empty set

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